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Debora [2.8K]
3 years ago
10

A 16-fl oz bottle of juice cost $2.00 what is the unit cost

Mathematics
1 answer:
irakobra [83]3 years ago
5 0
B, is the correct answer

$.125/fl oz
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Which of the following is equal to 51/3?
oee [108]
51/3 is equal to 17 hope it helps
7 0
3 years ago
Read 2 more answers
A man ran 20 miles in 2 hours. Calculate the average time that it took the man to run each mile in minutes.
konstantin123 [22]

Answer:

he ran 3 miles in 8 mins

Step-by-step explanation:

3 0
2 years ago
How do u do this promble
kupik [55]

Answer:

x = 10

Step-by-step explanation:

The total measures of a circle must add up to 360°.  In the diagram given there are two angles that are not given, however, both of these should be equal to each other.  That means that the sum of the other two angles ('5x - 5' and 93°) must be equal to the other angle of the same measure (138°):

5x - 5 + 93 = 138

Combine like terms: 5x + 88 = 138

Subtract 88 from both sides: 5x + 88 - 88 = 138 - 88 or 5x = 50

Divide by 5:  5x/5 = 50/5 or x = 10


7 0
3 years ago
What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3?
Zanzabum

Answer:

<h2>B. 468</h2>

Step-by-step explanation:

We have

a_1=156,\ r=\dfrac{2}{3}

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

S=\dfrac{a_1}{1-r}

Substitute:

S=\dfrac{156}{1-\frac{2}{3}}=\dfrac{156}{\frac{1}{3}}=156\cdot\dfrac{3}{1}=468

4 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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