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Oduvanchick [21]
3 years ago
10

the diagram shows two shaded shapes, A and B. shape A is formed by removing a sector of a circle with radius (3x-1)cm from a sec

tor of the circle with radius (5x-1)cm. Shape B is a circle of diameter (2-2x). The area of shape A is equal to the area of shape B. Find the value of x. ​
Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0
1234 the diagram shows two shaded shapes A and B
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Pedro can drive 2 times as fast as Pablo can ride his bicycle. If it takes Pablo 2 hours longer than Pedro to travel 72 miles, h
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Pablo can ride his bicycle with speed of 18 miles per hour

<u>Solution:</u>

Given, Pedro can drive 2 times as fast as Pablo can ride his bicycle.  

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Then the speed of the Pedro will be "2n" miles per hour

Now, If it takes Pablo 2 hours longer than Pedro to travel 72 miles,  

We have to find how fast can Pablo ride his bicycle?

<em><u>The formula for speed is given as:</u></em>

\text { distance }=\text { speed } \times \text { time }

Let the time taken by Pedro to travel 72 miles be "t" hours, then time taken by Pablo will be "t + 2" hours

<em><u>In case of Pablo:</u></em>

\begin{array}{l}{72 \text { miles }=\text { speed } \times (t+2) \text { hour }} \\ {\rightarrow 72=n \times(t+2) \rightarrow(1)}\end{array}

<em><u>In case of Pedro:</u></em>

\begin{array}{l}{72 \text { miles }=\text { speed } \times \text { thours }} \\ {\rightarrow 72=2 n \times t \rightarrow(2)}\end{array}

Then, equate both (1) and (2)

\begin{array}{l}{n \times(t+2)=2 n \times t} \\\\ {\rightarrow t+2=2 \times t} \\\\ {\rightarrow t+2=2 t} \\\\ {\rightarrow 2 t-t=2} \\\\ {\rightarrow t=2}\end{array}

Now, substitute t = 2 in (2)

\begin{array}{l}{\rightarrow 72=2 n \times 2} \\\\ {\rightarrow 72=4 n} \\\\ {\rightarrow n=18}\end{array}

Hence, the speed of Pablo is 18 miles per hour.

3 0
3 years ago
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