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Yakvenalex [24]
3 years ago
9

Students in Mr. Taylor's physics class conducted an experiment by dropping a basketball from a height of 40 feet and then record

ing the ball’s height after each bounce. The ball climbed to a height of 20 feet after the first bounce, and 10 feet after the second bounce. If this pattern continues, how many feet high will the ball climb after the third bounce? Input the answer using numbers only.
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

The answer would be 5 feet

Step-by-step explanation:

The class dropped the ball from 40 feet than after the ball bounced again it went to 20 feet than after the 2nd bounce it went to 10 feet and the pattern so far goes 40, 20, and 10. We need to find the common pattern of these 3 numbers and find the 4th number or x so to find the 4th number you can see that if you divide every number by 10 than you will get 4, 2, and 1 which you can see when divided by 2 every time goes to the next number so 4 divided  by 2 is 2 and 2 divided by 2 is 1 so we can assume 1 divided by 2 will be x divided by 10 so 1/2 is 0.5 so x divided by 10 is equal to 0.5 so the equation would be \frac{x}{10} =0.5 so we could multiply by 10 on both sides so we would get x = 5 so the final answer would be 5.

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Answer:

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Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

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using the SOHCAHTOA principle

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sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

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let the angle = ∅

cos ∅ = adjacent/hypotenuse

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cos ∅ =  0.784665392

∅ = cos-1  0.784665392

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sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

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Height of antenna  =  237.08 ft

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