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S_A_V [24]
3 years ago
15

What is the explicit formula for the geometric sequence: 224, 112, 56, 28, ... .

Mathematics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:

a_n=224(1/2)^n-1

Step-by-step explanation:

In this geometric sequence, we can see that the common ratio is 1/2 and the 1st term is 224. using this information, we can plug it into the geometric series formula and we get a_n=224(1/2)^n-1.

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How do you dilate a figure when the center of dilation is NOT the origin?
trasher [3.6K]

First, locate the center of dilation and then determine the distance of the points.

3 0
3 years ago
What is the distance between -12 and 32 on a number line?
Flura [38]

Answer:44

Step-by-step explanation:

from -12 to 0 is 12

from 0 to 32 is 32

12 +32 =44

3 0
3 years ago
Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th
HACTEHA [7]

Answer:

Required equation of tangent plane is z=\frac{6}{5}(x-5y-11).

Step-by-step explanation:

Given surface function is,

f(x,y)=6-\frac{6}{5}(x-y)

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)

So that,

f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}

f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}

f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6

Substitute all these values in (1) we get,

z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}

\therefore z=\frac{6}{5}(x-5y-11)

Which is the required euation of tangent plane.

4 0
3 years ago
Please help me with questions 21 and 22
valentina_108 [34]
I’m not sure abt 21 but 22 is the second one and the 4th one. So 2,4.
3 0
3 years ago
Which formula can be used to describe the sequence?<br><br> -2 2/3,-5 1/3,-10 2/3, -21 1/3, -42 2/3
Kaylis [27]

Correct answer is third option ---C in edge

4 0
3 years ago
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