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Dafna11 [192]
3 years ago
6

Drag each figure to show if it is similar to the figure shown or why it is not similar.

Mathematics
1 answer:
schepotkina [342]3 years ago
5 0

Answer:

Step-by-step explanation:

Similar figures have the same shape but the same size.

Moving from left to right:

The first figure is similar because it is rotated

The second figure is not similar because of shape

The third figure is not similar because of different ratio the ratio for the figure above is 3/5 or 0.6, while this figure is 12/15 or 0.8

The fourth figure is not similar because of ratio, but it is still a rectangle

The fifth figure is not similar because of shape

The last figure is similar because the ratio is the same with 6/10 or 0.6

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Can somebody help me with these, i will mark you brainliest :)
Diano4ka-milaya [45]

Answer:

11 is b

Step-by-step explanation:

thats all i can do sorry

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What is 25% 136 so I know
tigry1 [53]
It's 34.

You can either intuitively know 25% means one-fourth and divide 136 by 4

Or

Convert the percentage to a decimal and multiply. 136 * 0.25 = 34
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Total cost is $14 plus 10% tip
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Step-by-step explanation:

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If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

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What is the percentage of $1.35 of $5
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I believe that the answer would be 27%


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