Answer:
55 ft.
Step-by-step explanation:
First find the area of Lot X
67 • 70 = 4,690
Subtract the are of Lot X from the total area
8,375 - 4,690 = 3,685
3,685 is the area of Lot Y
Now divide 3,685 by the length of Lot Y : 67
3,685 ÷ 67 = 55
The width of Lot Y is 55 ft.
Hope this helps!
Answer:
equation for line: y = 5/3x -7/3
Step-by-step explanation:
The equation for a linear line is y = mx + c. m is the gradient of the line, also known as slope. So, m = 5/3.
Next we need to find c. Since we know a point the line must intersect, we can sub this into our line equation to get an answer:
(2,1) x=2,y=1
1 = 5/3*2 + c
1 = 10/3 + c
1 - 10/3 = c
3/3 - 10/3 = c
-7/3 = c
The final eqaution of the line is: y = 5/3x -7/3
<h2>
Answer: </h2>
59,425 sq mi
<h2>Step-by-step explanation: </h2>
When you want to round to the units place, you look at the digit in the number that is in the place to the right of that: the tenths place. Here, that digit is 7, which is more than 4. Because that digit is more than 4, 1 is added to the units place and all the digits to the right of that are dropped.
This gives you 59,424 +1 = 59,425.
If the tenths digit were 4 or less, no change would be made to values in the units place or to the left of that. The tenths digit and digits to the right would be dropped.
... 59,424.3 ⇒ 59,424 . . . . . for example
A, B, D are functions.
(First, second, and fourth response)
You can see which is function since for everyone input only has one value. You can also use the vertical line test.
This one is best done by elimination:
We need to start 4 meters away, so B is clearly wrong.
We first move towards Mr. Wilson (i.e. distance is decreasing) so A is wrong.
Our speed is faster on the way back, so the two sloped section must have differing slopes, so D is wrong.
(D also doesn't start at 4, it's wrong for two reasons.)
Only C is left.
We can check each part to make sure. First we start at 4m, then move away, then stay still (zero slope) for three seconds, then move back faster (higher slope). All parts check out ok.