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3 years ago

What is the percentage of $1.35 of $5

Mathematics

2 answers:

Elena-2011 [213]3 years ago

7 0

27 % is the answerrrrrrrrr

AnnyKZ [126]3 years ago

6 0

I believe that the answer would be 27%

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EASY— get marked brainliest!!!

Ilya [14]

Answer:

y≥1/2 x +1

Step-by-step explanation:

first the line in the graph is bold and not dotted

so the sign is either ≤ or≥

the shaded area is on the top , on this case it is greater than

the right answer is y≥1/2 x +1

7 0

3 years ago

In the first week of July a record 1120 people went to the local swimming pool in the second week 105 fewer people went to the p

Westkost [7]

Answer:

25%

Step-by-step explanation:

The number of people who went to the local swimming pool in the;

first week = 1120

second week ( 105 fewer people) = 1120 - 105 = 1015

third week (135 more people) = 1015 + 135 = 1150

fourth week (310 fewer people|) = 1150 - 310 = 840

The percent decrease in the number of people who went to the pool over these four weeks

= (1120 - 840)/1120 * 100%

= 280/1120 * 100%

= 1/4 * 100%

= 25%

It means that the number of people who went to the local swimming pool over the 4 weeks decreased by 25%

5 0

3 years ago

A.) find the test statistic

Arada [10]

Regarding the hypothesis tested in this problem, it is found that:

a) The test statistic is: t = 0.49.

b) The p-value is: 0.6297..

c) The null hypothesis is not rejected, as the p-value is greater than the significance level.

d) It appears that the students are legitimately good at estimating one minute, as the sample does not give enough evidence to reject the null hypothesis.

<h3>What is the test statistic?</h3>

The test statistic of the t-distribution is given by the equation presented as follows:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

In which the variables of the equation are given as follows:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the hypotheses.

s is the standard deviation of the sample.

n is the sample size.

The value tested at the hypothesis is:

$\mu = 60$

From the sample, using a calculator, the other parameters are given as follows:

$\overline{x} = 62.47, s = 19.2, n = 15$

Hence the test statistic is obtained as follows:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{62.47 - 60}{\frac{19.2}{\sqrt{15}}}$

t = 0.49.

<h3>What are the p-value and the conclusion?</h3>

The p-value is obtained using a t-distribution calculator, with a two-tailed test, as we are testing if the mean is different a value, in this case 60, with:

15 - 1 = 14 df, as the number of degrees of freedom is one less than the sample size.

t = 0.49, as obtained above.

Hence the p-value is of 0.6297.

Since the p-value is greater than the significance level of 0.01, the null hypothesis is not rejected, attesting to the ability of the students to estimate one minute.

More can be learned about the test of an hypothesis at brainly.com/question/13873630

#SPJ1

5 0

1 year ago

What multiplier would you use to decrease a value by 44%

11Alexandr11 [23.1K]

Answer:

I think the answer is4k3+0 or 4

8 0

3 years ago

16. Find the value of x*<br> 8. 2x-6<br><br> A 10 <br> B 7<br> C -7<br> D -10

Vikki [24]