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3 years ago

6

The probability of Mrs. Galvan randomly selecting a black pen from the 20 pens in her drawer is . Which of the following describ

es the likelihood of selecting a black pen?

1 answer:

aleksandrvk [35]3 years ago

7 0

I believe there is a 1/20 chance that Mrs. Galvan will pick a black pin. Since there are 20 pens, each pen has an equal chance of getting picked. For example, you have 2 pens and one of them is blue. The chance of me getting the blue pen is 1/2 or a 50% chance. So your answer will be 1/20 chance.

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find the Point of intersection of these 2 lines: y= 5x - 4 and y= 4x - 2 *write answer as (x,y) coordinate pair

harkovskaia [24]

The point of intersection is (2,6).

4 0

4 years ago

Evaluate if x =3 and y = -2: x squared + 2 y A. 5 B. 10 C. 2 D. 3

Luden [163]

Of you have 3 squared you get 9 then 2 times -2 is -4. then you add them 9=-4 which would be ...A: 5

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4 years ago

Read 2 more answers

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

How do you find the slope (m) and the y-intercept for (0,-4), (5,-4)?

navik [9.2K]

Answer:

In order to find the slope (m), and the y-intercept of this coordinate pair, you must complete rise over run.

This is represented by y2-y1, x2-x1. This can be represented like so:

-4-0 = -4

5--4 = 9

Here, we have concluded that our slope is -4/9.

Now, we must convert this into point slope form. Point slope form is y-y1=m(x-x1). This will look like this in our situation:

y+4=-4/9(x-0)

To solve, distribute the -4/9 first, which will leave you with:

y+4=-4/9x+0

Now, subract the 4 to both sides of the equation.

Our final answer looks like: y=-4/9-4.

<em>-</em>

<em>SLOPE: -4/9</em>

<em>Y INTERCEPT: -4 </em>

3 0

3 years ago

Which of the following equations is of the 2nd degree complete?

Komok [63]

Answer:

it's D

Step-by-step explanation:

i just know what I am talking about

4 0

3 years ago