What is the equation

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

8 0

I believe the answer is y=-9x-16 !

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Ms. Yung bought 18.5 pounds of candy to make treat bags for Halloween. If she plans on putting 0.2 pounds of candy in each bag,

laiz [17]

Answer:

92 treat bags

Step-by-step explanation:

In order to calculate the total amount of treat bags that Ms. Yung can make we would simply need to divide the weight of each bag's candy by the total weight of candy that Ms. Yung has. This would evenly divide the total amount of candy into as many bags as possible.

18.5 lbs. / 0.2lbs = 92.5 bags

Therefore, if we divide evenly Ms. Yung would be able to make a total of 92 treat bags because even though she has for half a bag left it would not be an entire treat bag like she wants.

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3 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

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3 years ago

Kylie ate lunch at a restaurant. The bill came to $74.60. If she left a 20% tip, what was the

IRINA_888 [86]

Answer:

total is 89.52

Step-by-step explanation:

20% >> .20

.20 * 74.60 = 14.92

14.92 + 74.60 = 89.52

Hope it Helps!

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