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hammer [34]
3 years ago
7

What is the equation

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
I believe the answer is y=-9x-16 !
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DOES ANYONE GET THIS??? Please help! WILL MARK BRAINLIEST!!!
zavuch27 [327]

Answer:

yes,

Step-by-step explanation:

For example, if it lands on 4, then u do 1*2*2*2*2 because it is 4, if 5, then do 1 *2*2*2*2*2, the two will change according to the hours.

4 0
3 years ago
HELPPP simplify the expression !!!
solong [7]

Answer:

Exact form: 3√5/5

Decimal form: 1.34164078...

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
2 years ago
14 over 15 divided by 28
Hoochie [10]

Answer:

1/30

Step-by-step explanation:

When we are dividing fractions, we can turn it into multiplication

14/15 divided by 28

14/15 x 1/28

14/420

simplified to 1/30

8 0
3 years ago
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I need help with 12 questions because idk how to do it and it's on metric units of liquid volume someone help quick I need to go
insens350 [35]
Where is the picture for this question
5 0
3 years ago
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