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natulia [17]
2 years ago
10

Lewis designs a game in which players work together to run a food truck business. During one game, the business loses $260. The

four players share the loss equally. Write and solve an equation to represent the change in profit for each player.
Mathematics
1 answer:
Ronch [10]2 years ago
3 0

Answer:

They each lost 65 dollars.

Step-by-step explanation:

Well they lost 260 dollars in total. 260/4 is 65. That means they now have however much money they had before -65.

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Pls help it’s easy but I been staring at this for 2 hours now pls help a lot of points and will give brainlyest
diamong [38]

Answer:?

I have no idea sir sorry yt ;-;

Step-by-step explanation:

5 0
3 years ago
the taco truck sells tacos for $3 and burritos for $4. the number of items sold on a tuesday is 125 with a total income of $430.
butalik [34]

Answer:

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

3 T + 4 B =425

T + B = 125

Where T is the number of tacos sold, and B is the number of burritos sold.

Multiplying the second equation by 3, and subtracting it to the first equation:

3 T + 4 B =425

3T + 3B = 375

___________

B =50

Replacing B in any equation:

T + B = 125

T +50 =125

T =125-50

T = 75

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
the standard addition algorithm below is being used to add three two-digit numbers 4z + 27 + x 5 equals y 14. If x, y, and z eac
Studentka2010 [4]
For the units positions of all numbers we have:
z+7+5=4 \\ z+12=4
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
z+12=14 \\ z=2

For the tens positions of all numbers we have:
4+2+x+1=1 \\ 7+x=1
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
7+x=11 \\ x=4

Now we insert x and z to find out y:
42+27+45=y14 \\ 114=y14 \\ y=1

Now we need to find out the product of these three numbers:
x*y*z=4*1*2=8
3 0
3 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
Geometry A Question! Help ASAP!
Gala2k [10]
I think the answer is B I am not sure!
8 0
3 years ago
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