Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer: 42 degrees
Explanation: KFD=84 KFL is half of KFD(84)
84 divided by 2 = 42
The answer is 10 1/2.
First you need to convert 4/5 and 7/10 so the denominator is the same. 4/5=8/10, 7/10 stays the same.
Now we add= 6 8/10 +3 7/10 =9 15/10.
9 15/10=10 5/10=10 1/2.
Hope this helps and hope you have a great day and please make brainiest
So your equation is

. You need to simplify this answer.
So first off, do 2x times 2x.
2 x 2 = 4.
Your equation is now

You're already off to a great start, so now let's add 4x + 7x. It is 11x.
Your equation is almost done! It's

right now.
Divide both sides by 11, and your answer is...
0.36363636 and so on, or you can round to the nearest hundreth, in which it will be
0.36.
I hope I helped!