Answer:
d=6
Step-by-step explanation:
divide 30 by 5 to get the value of d
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
Answer:
See below
Step-by-step explanation:
The values in the table change by $3.80 from one line to the next. Since each change from line to line changes in number of photos by 20, the average cost per photo is $3.80/20 = $0.19. There is apparently a $5.80 -3.80 = $2.00 shipping charge for numbers of photos in the range shown in the table.
Thus, the piecewise function has 3 pieces:
for x < 100: $2.00 + 0.19x
for x < 200: $4.50 + 0.17x
for x ≥ 200: $0.15x
This could be written as ...

We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>

To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting
from both sides of the equation
<u>This would give:</u>
f +
-
= 6 - 
f = 6 - 
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>

To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)