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2 years ago

Find x in the image below

Mathematics

1 answer:

Zanzabum2 years ago

8 0

Check the picture below.

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Find the volume of a right circular cone that has a height of 2.7 ft and a base with a diameter of 14.4 ft. Round your answer to

irina1246 [14]

Answer:

V≈146.57ft^3

Step-by-step explanation:

V=πr^2·h/3 since d is 14.4, we would divide it by 2 to find the radius which is 7.2

so V= π(7.2)^2· (2.7)/3

V≈146.57ft^3

It would be greatly appreciated if you gave me the brainlest

3 0

3 years ago

Select the correct answer.

mr Goodwill [35]

I believe its c because that is the suitable answer

6 0

2 years ago

Rewrite in simplest terms: 4(-5u +3) – 4(8u - 1)

viktelen [127]

Answer:

You distribute then combine

your answer is -52u+16

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Solve using long division Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

Which congruence postulate is this? SAS, SSS, AAS, ASA, HL

lara31 [8.8K]

Answer:

SAS

Step-by-step explanation:

6 0

3 years ago