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Wewaii [24]
3 years ago
6

4.7x 10^-1 as an ordinary number

Mathematics
1 answer:
Anon25 [30]3 years ago
7 0

0•47 as an ordinary number

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Convert (10111)2 into decimal number system​
Eva8 [605]

Answer:

(10111)_2 = (23)_{10}

Step-by-step explanation:

(10111)_2 = (1 \times 2^4) + (0 \times 2 ^3) + (1 \times 2^2) + (1 \times 2) + (1 \times 2^0)

            = 16 + 0 + 4 + 2 + 1\\=23

4 0
3 years ago
Amber put gasoline into her car she wrote down that she added 56.78 liters of gas but she rounded the amount to the nearest hund
Trava [24]

Answer:

56.779 or 56.782 56.778, etc, because it has to be 8 in the hundreths thousandths less than 5 or 7 in the hundreths thousandths greater than 5

7 0
3 years ago
A jar contains a mixture of 10 black balls, 8 red balls, and 2 white balls all the same size. What is the probability of drawing
gayaneshka [121]
Red 8/20 white 2/20 both 50% or 10/20
7 0
3 years ago
What is “2 1/2 x 3 1/3”
lesya692 [45]

Answer:

The answer is 8.3 bar notation.

Step-by-step explanation:

2 1/2 into improper is 5/2

3 1/3 into improper is 10/3

Now Multiply

5/2 x 10/3 is 300/36

Now Reduce.

25/3 = 8.3 bar notation

Mark Brainliest!

3 0
3 years ago
Read 2 more answers
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
4 years ago
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