Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Answer:
l = 16, w = 8
Step-by-step explanation:
Let l = length
Let w = width
Area = w * l
128 = w * l
w = 128/l
Perimeter = 2w + 2l
48 = 2w + 2l
48 = 2(128/l) +2l
48 = 256/l +2l
Multiply everything by l
48l = 256 + 2l^2
l^2 + 128 = 24l
l^2 + 128 -24l = 0
(l-16)(l-8)= 0
L = 16
L = 8
If you try them out, and test it, l = 16 would work:
2(16) + 256/16 = 48
32 + 16 =48
16 * 128/16 = 128
16 * 8= 128
128 = 128
Since I'm not sure if you are in advanced math or not, I will do it simple with guess and check
Try w is
Answer:
16 factors
Step-by-step explanation:
I hope this helps
Have an amazing day!