<span><span>(<span><span>4x</span>+1</span>)</span><span>(<span>x+3</span>)</span></span><span>
=<span><span>(<span><span>4x</span>+1</span>)</span><span>(<span>x+3</span>)</span></span></span><span>=<span><span><span><span><span>(<span>4x</span>)</span><span>(x)</span></span>+<span><span>(<span>4x</span>)</span><span>(3)</span></span></span>+<span><span>(1)</span><span>(x)</span></span></span>+<span><span>(1)</span><span>(3)</span></span></span></span><span>=<span><span><span><span>4<span>x2</span></span>+<span>12x</span></span>+x</span>+3</span></span><span>=<span><span><span>4<span>x2</span></span>+<span>13x</span></span>+<span>3</span></span></span>
I don’t think it would work it you solved for k instead of y. Because you’re solving for y when you do constant of proportionality. i’m not sure if i’m right or not but that’s what i think.
If you want you can rewrite the formula into slope intercept form so you don't get confused:
y=4x-2
Choice 1:
y=4x-2
y=4(-5)-2
y=-20-2
y=-22
y=4(0)-2
y=0-2
y=-2
y=4(3)-2
y=12-2
y=10
The best choice is the first one.
I hope this helped!
So in this one, we are DECREASING by 25%, so we say 25% of 820...
25% × 820 =
.25 × 820 = 205
Now since we are decreasing by 25%, we take our answer and subtract it from the original amount, 820.
820 - 205 = 615
820 decreased by 25% is
615.
The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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