Answer:
Step-by-step explanation:
Given,
Red marbles = 3,
Green marbles = 10,
So, the total marbles = 3 + 10 = 13,
Since, here replacement is not allowed,
Thus, the probability of getting a green marble and a red marble
= first red and second green + first green second red
Note : The probability of getting a green marble first and a red marble second
= 
Answer:
From smallest to greatest: -6, -3, 0, 1, 5
Step-by-step explanation:
The negative numbers will be on the left side of 0, and the positive numbers will be on the right side of 0.
Look at the coordinates and trace those points to a corresponding number on the x or y axis. Then write the first number in the coordinate in the x value and the second number for the y value, repeat the process for the rest of the points.
let's first off apply a log rule of cancellation, keeping in mind that, first off is ln(), not in(), and that ln() is just a shortcut to logₑ.
![\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ e^{ln(x)}\implies e^{log_e(x)}\implies x \\\\\\ \cfrac{d}{dx}\left[ e^{ln(x)} \right]\implies \cfrac{d}{dx}[x]\implies 1](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%0A%5C%5C%5C%5C%0Alog_a%20a%5Ex%20%3D%20x%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7B%5Cdownarrow%20%7D%7D%7Ba%5E%7Blog_a%20x%7D%3Dx%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0Ae%5E%7Bln%28x%29%7D%5Cimplies%20e%5E%7Blog_e%28x%29%7D%5Cimplies%20x%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%20e%5E%7Bln%28x%29%7D%20%5Cright%5D%5Cimplies%20%5Ccfrac%7Bd%7D%7Bdx%7D%5Bx%5D%5Cimplies%201)
Make it: y = mx + b form
b = y intercept
3y = -8x - 24
Divide by 3
y = -8/3x - 8
Answer: y intercept is -8
