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3 years ago

15

fun fact im terrible at math and i need help with another question lol The length of a rectangle is 15 cm and the width is 8 cm.

What is the perimeter of the rectangle?

1 answer:

S_A_V [24]3 years ago

6 0

Answer:

the perimeter of the rectangle is 46 cm.

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When a number x is multiplied by 6, the result is 38 .

serg [7]

X = 19/3

________
________

6 0

3 years ago

A high school has a total of 850 students. there are 60 more female students than there are make students?

Mrac [35]

Hey. Let me help you on this one.

Let's break this problem down so it's easier for us to comprehend it.

There are 850 students in the school, and the amount of female students equals to the amount of male students + sixty additional females.

Amount of students in school = 850 students

Male students = $X$

Female students = $X+60$

Let's form an equation so we can work with what we have.

$X+(X+60)=850$

Subtract 60 from both sides.

$X+X=790$

Simplify

$2X=790$

Divide both sides by 2.

$X=395$

Answer: There are 395 male students, and 455 female students.

3 0

3 years ago

PLS ANSWER. The questions is attached. Dont' put like I dont' know the answer if u don't know don't answer pls.

jekas [21]

Answer:

x = 2.4

Step-by-step explanation:

see image for explanation.

Hope it helps

8 0

2 years ago

Need help w this! will give brainliest and thanks to best answer :o) tysm<3

Montano1993 [528]

Answer:

A. They will pay more with the new price plan.

B. The new price plan would be cheaper.

Step-by-step explanation:

A. They will pay more with the new price plan.

For the current price plan, you would add the $3 rent to the two games (which are $4 each). This basically means:

$3 + $4 + $4 = $11

For the new price plan, you would add the $11 rent to the two games (which are $2 each). This basically means:

$11 + $2 + $2 = $15

Therefore, you pay more for the new price plan.

B. Using similar logic as part A, the current price plan 7 games would cost:

$3 + [7 x ($4)] = $31 (multiply by 7 since they play 7 games)

For the newprice plan, 7 games would cost:

$11 + [7 x ($2)] = $25 (multiply by 7 since they play 7 games)

Therefore, the new price plan would be cheaper.

Hope this helps :)

3 0

3 years ago

Read 2 more answers

Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t

svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 450, \sigma = 100$

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{550 - 450}{100}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 350

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{350 - 450}{100}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

$Z = \frac{X - \mu}{\sigma}$

$1.88 = \frac{X - 450}{100}$

$X - 450 = 1.88*100$

$X = 638$

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

$Z = \frac{X - \mu}{\sigma}$

$0.253 = \frac{X - 450}{100}$

$X - 450 = 0.253*100$

$X = 475.3$

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

$Z = \frac{X - \mu}{\sigma}$

$-0.385 = \frac{X - 450}{100}$

$X - 450 = -0.385*100$

$X = 411.5$

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

$Z = \frac{X - \mu}{\sigma}$

$0.385 = \frac{X - 450}{100}$

$X - 450 = 0.385*100$

$X = 488.5$

The middle 30% of the test scores is between 411.5 and 488.5.

7 0

3 years ago