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QveST [7]
3 years ago
6

Can u help me please

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

where's the number?

Step-by-step explanation:

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Sarah spends a total of $60. Based on the information in the table, how many people attended the craft demonstration?
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Divide 60 by however much people was there to get your answer


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3 years ago
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In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per
Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, P_0=450,000

Growth rate is, r=5\%=0.05

Final population is, P=700,000

A population growth is an exponential growth and is modeled by the following function:

P=P_0(1+r)^x

Taking log on both sides, we get:

\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}

Plug in all the given values and solve for 'x'.

x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10

So, for x > 9.13, the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0
3 years ago
Tamara has money in a savings account
olga2289 [7]

Answer:

  • 1.03a

Step-by-step explanation:

  • Amount in account = a
  • Interest rate = 3% per month

<u>Amount after a month:</u>

1. ........................

  • a*(1 + 0.03) =
  • 1.03a

2. ........................

  • a + 0.03a =
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4 0
3 years ago
Find the angle between u= V51 - 8; and v= 151+x. Round to the nearest tenth of a degree.
Igoryamba
Not sure if your trying to solve for x or v

6 0
3 years ago
If k=9 and x=5, find the value of the expression: <br> 2k - X<br><br> Please hurry
il63 [147K]

Answer:

\huge\boxed{13}

Step-by-step explanation:

= 2k - x

Given that k = 9, x = 5

= 2(9) - 5

= 18 - 5

= 13

\rule[225]{225}{2}

Hope his helped!

<h3>~AH1807</h3>
8 0
3 years ago
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