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lana [24]
2 years ago
7

Is 5 in the solution of x+3>8?

Mathematics
1 answer:
Ivan2 years ago
8 0

Answer: D) No; If x is 5, the expression on the left simplifies to 8, making the inequality false.

In other words, if x = 5, then x+3 becomes 5+3 which ultimately becomes 8, but this is not greater than 8 on the right side.

Your steps could look like this

x+3 > 8

5+3 > 8 ... replace x with 5

8 > 8 ... this is a false inequality

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To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points.
8 0
2 years ago
The heights of two elevators can be modelled by linear functions. At time t = 0, Elevator A is 16 feet above ground floor. It de
Tomtit [17]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me with this!
ivanzaharov [21]

1.  The first equation is - 2x + 5y = 0

Second equation is y = \frac{2}{5} x

5y = 2x

- 2x + 5y = 0

Hence, the two equations are equivalent.

2.  a_{1} = 2, a_{2} = - 2

b_{1} = -1,  b_{2} = -1

\frac{a_{1} }{a_{2}} =\frac{2}{-2} = -1

\frac{b_{1} }{b_{2}} = \frac{-1}{-1}  = 1

\frac{a_{1} }{a_{2}} \neq \frac{b_{1} }{b_{2}}

Hence, the equations are consistent.

3.   a_{1} = 4, a_{2} = 6

b_{1} = -1, b_{2} = -1

\frac{a_{1} }{a_{2}} =\frac{4}{6} = \frac{2 }{3}

\frac{b_{1} }{b_{2}} = \frac{-1}{-1} = 1

\frac{a_{1} }{a_{2}} \neq \frac{b_{1} }{b_{2}}

Hence, the equations are consistent.

4.  Equations can be re-arranged as:

x + y - 4 = 0 and

x + y + 6 = 0

a_{1} = 1, a_{2} = 1

b_{1} = 1, b_{2} = 1

c_{1} = -4, c_{2} = 6

\frac{a_{1} }{a_{2}} =\frac{1}{1} = 1

\frac{b_{1} }{b_{2}} =\frac{1}{1} = 1

\frac{c_{1} }{c_{2}} =\frac{-4}{6} = \frac{-2}{3}

\frac{a_{1} }{a_{2}} = \frac{b_{1} }{b_{2}} \neq \frac{c_{1} }{c_{2}}

Hence, the equations are inconsistent.

5.  If we multiply the first equation by 4, we will get,

2y = -4x + 20 which is the second equation.

Hence, the equations are equivalent.

4 0
3 years ago
Really could use help here.
marishachu [46]

Answer:

\mathsf {y =\frac{15}{7}x } < \mathsf {y=\frac{13}{6}x } < \mathsf {y=\frac{11}{5}x } < \mathsf {y=\frac{21}{9}x } < \mathsf {y= \frac{19}{8}x}

Step-by-step explanation:

<u>Finding the unit rate of the graph</u> :

  • Take 2 points and find the slope
  • ⇒ (0,0) and (12, 25)
  • ⇒ m = 25 - 0 / 12 - 0
  • ⇒ m = <u>25/12</u>
  • The equation is : <u>y = 25/12x</u>

Now, the equations with greater unit rates (in increasing order) are :

  • \mathsf {y =\frac{15}{7}x } < \mathsf {y=\frac{13}{6}x } < \mathsf {y=\frac{11}{5}x } < \mathsf {y=\frac{21}{9}x } < \mathsf {y= \frac{19}{8}x}
8 0
1 year ago
Rectangle MNOP is shown below. Aiden argues that MNQ is congruent to POQ. What triangle congruence criteria proves that MNQ is c
Katena32 [7]

Answer:

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Step-by-step explanation:

Given:

m∠NQM = 40°

m∠NQO = 100°

MNOP is a Rectangle

So we can say that:

Property of rectangle:

All angles of rectangle are 90°

Opposite sides of Rectangle are equal and parallel to each other

MN ≅ PO (opposite side of rectangle)

∠NMQ ≅ ∠OPQ (Both angles are 90°)

Now By Straight Angle property

m∠NQM + m∠NQO + m∠OQP = 180° (angles of straight line)

Substituting the values we get;

40° + 100° + m∠OQP = 180°

140° + m∠OQP = 180°

m∠OQP = 180° - 140° = 40°

So m∠OQP = m∠NQM = 40°

m∠OQP ≅ m∠NQM (Equals angles are congruent to each other)

Hence In Δ MNQ and Δ POQ

m∠OQP ≅ m∠NQM

∠NMQ ≅ ∠OPQ (Both angles are 90°)

MN ≅ PO (opposite side of rectangle)

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Hence Proved...

7 0
3 years ago
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