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2 years ago

Is 5 in the solution of x+3>8?

Mathematics

1 answer:

Ivan2 years ago

8 0

Answer: D) No; If x is 5, the expression on the left simplifies to 8, making the inequality false.

In other words, if x = 5, then x+3 becomes 5+3 which ultimately becomes 8, but this is not greater than 8 on the right side.

Your steps could look like this

x+3 > 8

5+3 > 8 ... replace x with 5

8 > 8 ... this is a false inequality

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2 years ago

The heights of two elevators can be modelled by linear functions. At time t = 0, Elevator A is 16 feet above ground floor. It de

Tomtit [17]

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3 years ago

Read 2 more answers

Please help me with this!

ivanzaharov [21]

1. The first equation is - 2x + 5y = 0

Second equation is $y = \frac{2}{5} x$

5y = 2x

- 2x + 5y = 0

Hence, the two equations are equivalent.

2. $a_{1} = 2, a_{2} = - 2$

$b_{1} = -1, b_{2} = -1$

$\frac{a_{1} }{a_{2}} =\frac{2}{-2} = -1$

$\frac{b_{1} }{b_{2}} = \frac{-1}{-1} = 1$

$\frac{a_{1} }{a_{2}} \neq \frac{b_{1} }{b_{2}}$

Hence, the equations are consistent.

3. $a_{1} = 4, a_{2} = 6$

$b_{1} = -1, b_{2} = -1$

$\frac{a_{1} }{a_{2}} =\frac{4}{6} = \frac{2 }{3}$

$\frac{b_{1} }{b_{2}} = \frac{-1}{-1} = 1$

$\frac{a_{1} }{a_{2}} \neq \frac{b_{1} }{b_{2}}$

Hence, the equations are consistent.

4. Equations can be re-arranged as:

x + y - 4 = 0 and

x + y + 6 = 0

$a_{1} = 1, a_{2} = 1$

$b_{1} = 1, b_{2} = 1$

$c_{1} = -4, c_{2} = 6$

$\frac{a_{1} }{a_{2}} =\frac{1}{1} = 1$

$\frac{b_{1} }{b_{2}} =\frac{1}{1} = 1$

$\frac{c_{1} }{c_{2}} =\frac{-4}{6} = \frac{-2}{3}$

$\frac{a_{1} }{a_{2}} = \frac{b_{1} }{b_{2}} \neq \frac{c_{1} }{c_{2}}$

Hence, the equations are inconsistent.

5. If we multiply the first equation by 4, we will get,

2y = -4x + 20 which is the second equation.

Hence, the equations are equivalent.

4 0

3 years ago

Really could use help here.

marishachu [46]

Answer:

$\mathsf {y =\frac{15}{7}x }$ < $\mathsf {y=\frac{13}{6}x }$ < $\mathsf {y=\frac{11}{5}x }$ < $\mathsf {y=\frac{21}{9}x }$ < $\mathsf {y= \frac{19}{8}x}$

Step-by-step explanation:

Finding the unit rate of the graph :

Take 2 points and find the slope
⇒ (0,0) and (12, 25)
⇒ m = 25 - 0 / 12 - 0
⇒ m = 25/12
The equation is : y = 25/12x

Now, the equations with greater unit rates (in increasing order) are :

$\mathsf {y =\frac{15}{7}x }$ < $\mathsf {y=\frac{13}{6}x }$ < $\mathsf {y=\frac{11}{5}x }$ < $\mathsf {y=\frac{21}{9}x }$ < $\mathsf {y= \frac{19}{8}x}$

8 0

1 year ago

Rectangle MNOP is shown below. Aiden argues that MNQ is congruent to POQ. What triangle congruence criteria proves that MNQ is c

Katena32 [7]

Answer:

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Step-by-step explanation:

Given:

m∠NQM = 40°

m∠NQO = 100°

MNOP is a Rectangle

So we can say that:

Property of rectangle:

All angles of rectangle are 90°

Opposite sides of Rectangle are equal and parallel to each other

MN ≅ PO (opposite side of rectangle)

∠NMQ ≅ ∠OPQ (Both angles are 90°)

Now By Straight Angle property

m∠NQM + m∠NQO + m∠OQP = 180° (angles of straight line)

Substituting the values we get;

40° + 100° + m∠OQP = 180°

140° + m∠OQP = 180°

m∠OQP = 180° - 140° = 40°

So m∠OQP = m∠NQM = 40°

m∠OQP ≅ m∠NQM (Equals angles are congruent to each other)

Hence In Δ MNQ and Δ POQ

m∠OQP ≅ m∠NQM

∠NMQ ≅ ∠OPQ (Both angles are 90°)

MN ≅ PO (opposite side of rectangle)

Δ MNQ ≅ Δ POQ ( BY Angle Angle Side)

Hence Proved...

7 0

3 years ago