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ArbitrLikvidat [17]
3 years ago
11

Solve 0 = - x^2 + 10x - 8

Mathematics
1 answer:
Bogdan [553]3 years ago
5 0

Answer:

x = 5 +- √17

Step-by-step explanation:

0 = -x^2 + 10x - 8

-(-x^2 + 10x - 8) = 0

Now do the quadratic formula with x^2 - 10x + 8 = 0

a = 1

b = -10

c = 8

x =  \frac{  - ( - 10) +  -  \sqrt{( -  {10)}^{2}  - 4 \times 1 \times 8} }{2 \times 1}

x = \frac{10 +  -  \sqrt{17} }{2}

x = 5 +  \sqrt{17}

x = 5 -  \sqrt{17}

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Suppose that we test the hypotheses LaTeX: H_0 H 0 : LaTeX: \mu=50 μ = 50 LaTeX: H_a H a : LaTeX: \mu&gt;50 μ &gt; 50 Further su
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Which is the sum of the interior angles of an octagon?
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Note that no diagram is drawn to scale.


If the diagram in the first picture is further worked upon, we have polygon ABCDE.

Note also that line AD = 18in and line MD = 10in.
This simply means the line Am = AD - MD = 8in.

We have the height of the triangle needed to solve for the area of the triangle. Area of Triangle = 1/2×b×h
Where b is length base of the triangle and h is the length of height of the triangle.
We still need b to find the Area.

Note also that two opposite sides of parallelograms are equal. This implies that line DC = line EB which is equal to 14in.
In the third image, you can see this. Half the length of the side of the parallelogram is needed. This means 14/2 = 7in.

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Area =  \frac{1}{2} (7 \times 8)
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Area of parallelogram EBCD = bh

Where b is the length of the base side and h is the height.
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Your answer is 356in.

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