<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.
As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation
∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
Answer:
∞
Step-by-step explanation:
I assume you meant 3×10 + 3456/3629 + 2341×123 + 123 ∞×90 and x is multiplication and not a variable.
Answer:
If the second of the three numbers is
n
, then the first and third are
n- 1
and n
+
1
, so we find:
117
=
(
n
−
1
)
+
n
+
(
n
+
1
)
=
3n
Dividing both ends by
3 we find:
n
=
117/ 3
=
39
So the three numbers are:
38
,
39
,
40
Step-by-step explanation : I hope it helps please don't forget to mark me brainliest . :)
The correct reason <span>for each step in the solution of the equation would be as follows:
</span>
12 − 5x + 6x = 4 - Given
12 + x = 4 - Combine Like Terms
x= −8 - Subtraction Property of Equality
Hope this answers the question. Have a nice day.
