Perimeter of 316 and 67 m
2 answers:
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Answer:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
Solution to the problem
For this case we have the following distribution given:
X 0 1 2 3 4
P(X) 0.4096 0.4096 0.1536 0.0256 0.0016
And we satisfy that and
so we have a probability distribution. And we can find the expected value with the following formula:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.