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Tamiku [17]
3 years ago
9

Ratio number 1.50:1.38

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0
The answer is 75:69 hope this helps ::))
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What is the quotient? <br> X+5/3x^2 + 4x+5
nasty-shy [4]

Answer:

3x - 11

Step-by-step explanation:

x + 5/ 3x-11

3x - 11 is the quotient

5 0
2 years ago
How do you graph? <br> y=−4/3x+8y
trasher [3.6K]

How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).


In this case, we must first isolate y.


y = (-4/3)x + 8y


y - 8y = (-4/3)x


-7y = (-4/3)x


y = (-4/3)x ÷ (-7)


y = (4/21)x


Now follow the steps above.


8 0
3 years ago
Please help me out? thank you!!!
NeX [460]

Step-by-step explanation:

What you need to do is convert the quarts into gallons and then you need to subtract the number by 2 and you have your answer. Sorry I cannot give you the answer! I'm kinda in a rush but I wanted to help you out.

8 0
3 years ago
Read 2 more answers
A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walkercharge for a 45 minute w
leonid [27]

hello

from the question given, the dog walker charges a flat rate of $6 and an extra $30 per hour.

we can write out an equation in function notation

let the number of hours be represented by x

f(x)=6+30x

now we can proceed to solve the cost of the walk for 45 minutes

\begin{gathered} 1hr=60\min s \\ \text{xhr}=45\min s \\ x=\frac{45}{60} \\ x=\frac{3}{4} \\ \text{therefore 45mins = 3/4 hours} \end{gathered}

now we can input the value into the equation and know the cost for 45 minutes walk

\begin{gathered} f(x)=6+30x \\ x=\frac{3}{4} \\ f(x)=6+30(\frac{3}{4}) \\ f(x)=6+22.5 \\ f(x)=28.5 \end{gathered}

from the calculation above, the cost of 45 minutes walk will cost $28.5

6 0
1 year ago
Pls help is due tomorrow and if u help i will give u brainliest
Reil [10]

Answer:

Search it up

Step-by-step equation:

Just search up the website at the bottom of the paper.

6 0
3 years ago
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