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Travka [436]
3 years ago
14

What’s the answer to these?

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0
10= 4
11= 3
12= 1
Hope this helps
You might be interested in
11. Find the coordinates of A' and B'if A (3,5) and B (-7, 3) undergo
NISA [10]
<h2>Answer:(-3,-5),(7,-3)</h2>

Step-by-step explanation:

If a point (x,y) gets reflected about origin,the new point formed after reflection is (-x,-y).

Given that A=(3,5),

So,A'=(-3,-5)

Given that B=(-7,3),

So,B'=(-(-7),-3)=(7,-3)

4 0
3 years ago
Find the equation of the line passing through the points -2x+1 (8,2)
Harrizon [31]

The line that passes through (-2, 1) and (8, 2) is:

y = (1/10)*x + 12/10

<h3>How to find the equation of the line?</h3>

I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).

A general linear equation is written as:

y = a*x + b

If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

a = \frac{y_2 - y_1}{x_2 - x_1}

In this case, we know that it passes through (-2, 1) and (8, 2), then:

a = \frac{2 - 1}{8 - (-2)} = 1/10

Then the line is:

y = (1/10)*x + b

To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.

2 = (1/10)*8 + b

2 - 8/10  = b

20/10 - 8/10 = b

12/10 = b

Then the linear equation is:

y = (1/10)*x + 12/10

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

4 0
2 years ago
Solve the equation 3/x-4=1/5​
rosijanka [135]

Answer:

The very first thing we want to do in this equation is to isolate x on one side (preferably the left side).

3/x - 4 = 1/5

We get rid of any constants first, by performing the inverse property;

The inverse property of subtraction is addition, so we add 4 to both sides:

+4        +4

3/x = 4 1/5

3 is being divided by x, so the inverse operation of division is multiplication. So we multiply by 1/3 on both sides.

x1/3    x1/3

X = 1 4/10 which simplifies to 1 2/5.

7 0
2 years ago
What is the lateral surface area of this right pyramid with a square base?
Brums [2.3K]

Answer:

The lateral surface area of a square pyramid is the sum of the areas of the side faces only, whereas the surface area is the lateral area + area of the base. The lateral area of a square pyramid = 2al (or) 2a√[(a 2 /4) + h 2]. To get the surface area, we need to add the area of the base (which is a 2) to each of these formulas.The surface area of a square pyramid = a 2 + 2al (or) a 2 + 2a[(a 2 /4) + h 2]. where, a = Length of the base (square) l = slant height; h = height of the pyramid.

Step-by-step explanation:

hope this helps if not let me know have a great day :)

7 0
2 years ago
I need 5 lines with a undefined slope
algol13

Answer:

x=1

x=2

x=3

x=4

x=5

??I'm pretty sure thats what u wanted

4 0
3 years ago
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