Y= -1/3 x
y= mx+ c
m is -1/3
Answer: There are 12 white and blue cars more than silver and red cars
Number of white cars: n1=25
Number of blue cars: n2=17
Number of white and blue cars: n3=n1+n2=25+17→n3=42
Number of silver cars: n4=21
Number of red cars: n5=9
Number of silver and red cars: n6=n4+n5=21+9→n6=30
How many more white and blue cars are there than silver and red cars?
n=?
n=n3-n6=42-30→n=12
Answer: There are 12 white and blue cars more than silver and red cars.
Answer:
answer A
Step-by-step explanation:
Because
Answer:
Step-by-step explanation:
perp. -3/2
y + 1 = -3/2(x - 4)
y + 1 = -3/2x + 6
y = -3/2x + 5
Answer:
that put into the advanced course is 396.75
Step-by-step explanation:
The computation of that put into the advanced course is shown below:
P(X>60)
= P((X - mean) ÷ s > (60 - 50) ÷ 10)
= P (Z > 1)
= 0.1587
It could be checked by the standard normal table
Now that put into the advance course is
= 2,500 × 0.1587
= 396.75
Hence, that put into the advanced course is 396.75
