Answer:
1/4 - 1/8 = 2/8 - 1/8 = 1/8
F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
LEts start with 10^1
If we have positive exponent then we add zeros
10^1= 10
(Put 2 zeros because exponent is 2)
(Put 3 zeros because exponent is 3)
(Put 4 zeros because exponent is 4)
(Put 5 zeros because exponent is 5)
For negative exponent , we make a fraction . we put 1 at the top always and number as the bottom
(Put 1 zero at the bottom because exponent is -1)
(Put 2 zeros at the bottom because exponent is -2)
(Put 3 zeros at the bottom because exponent is -3)
