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aalyn [17]
4 years ago
8

Jonathan needs to cover 3/4 miles. He already covered 1/6 mile. How

Mathematics
2 answers:
mrs_skeptik [129]4 years ago
4 0

Answer:

3/4-1/6

=(9-2)/12

=7/12

Oksana_A [137]4 years ago
4 0

Answer:

x = 3 / 4 - 1 / 6

x = 9 / 12 - 2 / 12

x = 7 / 12 of a mile

Step-by-step explanation:

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What is the product of -2x^3 + x -5 and x^3 – 3x?
lana66690 [7]
(-2x^3 +x -5) * (x^3 -3x)
= x^6*(-2*1) +x^4*(-2*-3 +1*1) +x^3*(-5) +x^2*(-3) +x(-5*-3)
= -2x^6 +7x^4 -5x^3 -3x^2 +15x
8 0
4 years ago
Hey Bestie! 50 pts Pls help! Real answers only pls <3
frosja888 [35]

Answer:

1. \: 3i

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2>1. \:  \sqrt{ - 9}</h2>

\sqrt{ - 1(9)}

\sqrt{ - 1}  \times  \sqrt{  9}

i \times  \sqrt{9}

i \times  \sqrt{ {3}^{2} }

i \times 3

3i

<h2>2. \:  \sqrt{ - 8}</h2>

\sqrt{ - 1(8)}

\sqrt{ - 1}  \times  \sqrt{8}

i \times  \sqrt{8}

i \times  \sqrt{ {2}^{2} \times 2 }

2i \sqrt{2}

<h2>3. \:  \sqrt{ - 80}</h2>

\sqrt{ - 1}  \times  \sqrt{80}

i \times  \sqrt{80}

4i \:  \sqrt{5}

<h2>4. \:  \sqrt{ - 75}</h2>

\sqrt{ - 1}  \times   \sqrt{75}

i \times  \sqrt{75}

i \times  \sqrt{ {5}^{2} \times 3 }

5i \sqrt{3}

<h2>5. \:  \sqrt{ - 72}</h2>

\sqrt{ - 1}  \times  \sqrt{72}

i \times  \sqrt{72}

i \times ( {6}^{2}  \times 2)

6i \sqrt{2}

<h2>6.  \sqrt{ - 20}</h2>

\sqrt{ - 1}  \times  \sqrt{20}

i \times  \sqrt{20}

i \times  \sqrt{ {2}^{2}  \times 5}

2i \sqrt{5}

<h2>7. \:  \sqrt{ - 27}</h2>

\sqrt{ - 1}  \times  \sqrt{27}

i \times  \sqrt{27}

i \times  \sqrt{ {3}^{2}  \times 3}

3i \sqrt{3}

<h2>8. \:  \sqrt{ - 12}</h2>

\sqrt{ - 1 \times 12}

i \times  \sqrt{12}

i \times  \sqrt{4(3)}

2i \sqrt{3}

<h2>9. \:  \sqrt{ - 125}</h2>

\sqrt{ - 1}  \times  \sqrt{125}

i \times  \sqrt{ {5}^{2} \times 5 }

5i \sqrt{5}

<h2>10. \:  \sqrt{ - 180}</h2>

\sqrt{ - 1}  \times  \sqrt{180}

i \times  \sqrt{ {6}^{2} \times 5 }

6i \sqrt{5}

<h3>Hope it is helpful...</h3>
5 0
3 years ago
Anything will help please
svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

8 0
2 years ago
In a poll to pick the name of a new planet discovered in a distant solar system, a total of 963 scientists voted. There were fou
jarptica [38.1K]

Answer:

195

Step-by-step explanation:

Let wining name have, x votes

1st = x

2nd = x - 53

3rd = x - 79

4th = x - 105

x + (x - 53) + (x - 79) + (x - 105) = 963

x + x - 53 + x - 79 + x - 105 = 963

4x - 237 = 963

4x = 963 + 237

4x = 1200

x = 1200 / 4

x = 300

4th = x - 105

x - 105 = 300 - 105 = 195

3 0
3 years ago
What is 5 1/2 x 2 1/3 ?
shutvik [7]
5 1/2 * 2 1/3 =
11/2 * 7/3 =
77/6 =
12 5/6 <===
3 0
3 years ago
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