3 years ago

Work out the acceleration for the first 3 seconds?

2 answers:

5 0

The acceleration is given by the slope of the line. This line passes through the points (0, 2) and (3, 5), so it has slope

$\dfrac{5-2}{3-0}=1$

which means the acceleration over this 3 second interval is 1 m/s^2.

Setler [38]3 years ago

5 0

Answer:

1 ms^(-2)

Step-by-step explanation:

Acceleration = velocity difference/time

= (5-2)ms^-1/3s

= 3ms^-1 / 3s

= 1ms^-2

Hope it helps you and if it does, please mark me brainliest...

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