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3 years ago

WORTH 40 POINTS PLEASEEEEEE ANSWER

Mathematics

1 answer:

Illusion [34]3 years ago

7 0

p(x) = 1/2 x - 3

1) Type of function: linear function

2) Doman: all real number

3) Range: all real number

4) x-intercept:

1/2 x - 3 = 0

1/2 x = 3

x = 3 * 2

x = 6

x-intercept: (6 , 0)

5) y-intercept: x = 0; y = -3

So y-intercept: (0, -3)

6) p(x) = 1/2 x - 3

x = 0; y = -3

x = 1, y = - 5/2

x = 2 , y = - 2

x = 4, y = -1

x = 6, y = 0

x = 8, y = 1 and so on....

The output values increase as the input values increase. so it's increasing.

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Right because if you make a triangle like that than you make a right a right angle

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Solve 2x + 8 < 10 or 2x + 8 > 20.

jasenka [17]

Answer:

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Step-by-step explanation:

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2 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

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Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

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b is the base of rectangle

h is the height of rectangle

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$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

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$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Hope this helped! Let me know if you have any more questions.

3 0

3 years ago