Answer:
Only vowels and odd numbers:

Spells math:

Step-by-step explanation:
We have four letters, so the probability that one letter is a vowel is 5/26 (we have 5 vowels in a total of 26 letters), then the second letter has a probability of 4/25 of being a vowel (1 vowel used), and so on (third letter being vowel = 3/24 and fourth letter being vowel = 2/23)
Then, for the digits, we do the same, one digits has 5/10 probability of being odd, then the second digit has 4/9, the third has 3/8 and the fourth has 2/7.
So the final probability would be:

To find the probability that the password spells the word “MATH", each letter has to be a specific letter, so the first letter has 1/26 probability, the second has 1/25, and so on:

Answer:
14w
Step-by-step explanation:
Answer:
False
Step-by-step explanation:
Consider the equations with the same number of equations and variables as shown below,
<u>Case 1</u>

This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.
<u>Case 2</u>

This equation has infinitely many possible solutions.
Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.
X^2 + 8x + 7 = 0
x^2 + 7x + x + 7 = 0
x(x + 7) + 1(x + 7) = 0
(x + 7) (x + 1) = 0
x = -7 or x = -1