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Troyanec [42]
2 years ago
8

6 = -w/8 what is this answer ?

Mathematics
2 answers:
garri49 [273]2 years ago
7 0

Answer:

w = -48

Step-by-step explanation:

6 = -w/8

Multiply each side by -8

6*-8 = -w/8*-8

-48 = w

Ahat [919]2 years ago
7 0

Answer:

  • w=-48

Step-by-step explanation:

  • 6=-w/8
  • -w=48
  • w=-48
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The initial population of a town in the year 2010 was 20 000. By 2014, the population had grown exponentially to 32 500 people.
stiv31 [10]

Answer:

  P = 20000×1.625^(n/4)

Step-by-step explanation:

An exponential equation can be written using the given data:

  value = (initial value)×(growth factor in period)^(n/(period))

Here, the growth is by a factor of 32500/20000 = 1.625, and the period is 4 years. Then your exponential equation is ...

  P = 20000×1.625^(n/4)

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3 years ago
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

  • CDs — $10,000
  • bonds — $80,000
  • stocks — $45,000

Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

  c + b + s = 135000 . . . . . . . . . . . . . . . . . total invested

  0.0275c +.045b +0.104s = 8555 . . . . . total income earned

  -c + b = 70000 . . . . . . . . . . . . . . . . . . . . . 70,000 more was in bonds than CDs

Using the third equation to write an expression for b, we can substitute into the other two equations.

  b = 70000 +c . . . . . . . . . . . . . . . . expression we can substitute for b

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  2c +s = 65000 . . . . . . . . . . . . . . . . [eq4] simplify

  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

  .0725c +.104s = 5405 . . . . . . . . . . [eq5] simplify

Using [eq4], we can write an expression for s that can be substituted into [eq5].

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  0.0725c +0.104(65000 -2c) = 5405

  -0.1355c = -1355 . . . . . . . . . . . . . . . . . . . . subtract 6760, simplify

  c = 1355/.1355 = 10,000

  s = 65000 -2×10000 = 45,000

  b = 70000 +10000 = 80,000

The amounts invested in stocks, bonds, and CDs were $45,000, $80,000, and $10,000, respectively.

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Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

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3 years ago
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Answer:

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This equation is written in <em>standard form</em>, so we need to change it into <em>slope-intercept form.</em>

<em />

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The slope is classified as "m" in this type of equation, so, the slope is -3.

Best of Luck!

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