If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
Answer:
To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.
(
x
+
5
)
(
x
+
2
)
becomes:
(
x
×
x
)
+
(
x
×
2
)
+
(
5
×
x
)
+
(
5
×
2
)
x
2
+
2
x
+
5
x
+
10
We can now combine like terms:
x
2
+
(
2
+
5
)
x
+
10
x
2
+
7
x
+
10
Step-by-step explanation:
Answer:
56.
Step-by-step explanation:
= -(8-12)+60+(-4)*2
= -(-4)+60+(-4)*2
= 4+60+(-4)*2
= 4+60+-4*2
= 4+60-4*2
= 4+60-8
= 64-8
= 56
It’s 23/4 42 so if you have bla bla bla you get bla bla bla do you get it
