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ANEK [815]
3 years ago
11

Which graph does not represent a function ?

Mathematics
1 answer:
baherus [9]3 years ago
4 0

Answer: the the 2nd circular one

Step-by-step explanation: Functions can't just go in a circle, they will repeat the x value

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Drag the tiles to the correct boxes to complete the pairs, not all tiles will be used.
Ann [662]

Answer:

I can't answer your question because I can't see what boxes your talking about

8 0
2 years ago
What is x and y? 2x-2y=-4 2x+y=11 Is there infinitely many solutions, 1 solution, or no solution? solve by elimination.
Kaylis [27]

Let's solve your system by substitution.

2x−2y=−4;2x+y=11

Rewrite equations:

2x+y=11;2x−2y=−4

Step: Solve2x+y=11for y:

2x+y=11

2x+y+−2x=11+−2x(Add -2x to both sides)

y=−2x+11

Step: Substitute−2x+11foryin2x−2y=−4:

2x−2y=−4

2x−2(−2x+11)=−4

6x−22=−4(Simplify both sides of the equation)

6x−22+22=−4+22(Add 22 to both sides)

6x=18

6x/6 = 18/6

(Divide both sides by 6)

x=3

Step: Substitute3forxiny=−2x+11:

y=−2x+11

y=(−2)(3)+11

y=5(Simplify both sides of the equation)

Answer:

x=3 and y=5

5 0
2 years ago
Consider the diagram below.
Elza [17]

Answer: 110

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B500%7D%20" id="TexFormula1" title=" \sqrt{500} " alt=" \sqrt{500} " align="absmid
DochEvi [55]
The square root of 500 is 22.3607
4 0
3 years ago
Read 2 more answers
An employment agency specializing in temporary construction help pays heavy equipment operators
pochemuha
Answer:
Number of heavy equipment operators hired were 22
Number of general laborers hired were 11

Explanation:
Assume that number of heavy equipment operators hired is x and that number of general laborers is y.

We are given that:
1- Total number of hired people is 33. This means that:
x + y = 33
This can be rewritten as:
x = 33 - y ...........> equation I
2- heavy equipment operators are paid $135, general laborers are paid $89 and that the total payment was $3949. This means that:
135x + 89y = 3949 ............> equation II

Substitute with equation I in equation II and solve for y as follows:
135x + 89y = 3949
135(33-y) + 89y = 3949
4455 - 135y + 89y = 3949
506 = 46y
y = 506 / 46
y = 11

Substitute with y in equation I to get the value of x as follows:
x = 33 - y
x = 33 - 11
x = 22

Hope this helps :)
4 0
2 years ago
Read 2 more answers
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