Answer:
C, x^3+x^2−7x−15
Step-by-step explanation:
=(x+−3)(x^2+4x+5)
=(x)(x^2)+(x)(4x)+(x)(5)+(−3)(x^2)+(−3)(4x)+(−3)(5)
=x^3+4x^2+5x−3x^2−12x−15
=x^3+x^2−7x−15
The years when the Russo-Japanese war had not yet happened is the year of 1903 and before
Let x represents years, the inequality system is x < 1904
Answer:
Area segment = 3/2 π - (9/4)√3 units²
Step-by-step explanation:
∵ The hexagon is regular, then it is formed by 6 equilateral Δ
∵ Area segment = area sector - area Δ
∵ Area sector = (Ф/360) × πr²
∵ Ф = 60° ⇒ central angle of the sector
∵ r = 3
∴ Area sector = (60/360) × (3)² × π = 3/2 π
∵ Area equilateral Δ = 1/4 s²√3
∵ The length of the side of the Δ = 3
∴ Area Δ = 1/4 × (3)² √3 = (9/4)√3
∴ Area segment = 3/2 π - (9/4)√3 units²
$9,900
10% off of 10,000 is 9,000
10% more than 9,000 is 9,900
