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Ronch [10]
3 years ago
14

The Russo-Japanese War was a conflict between Russia and Japan that started in the year 1904. Let x represent any year. Write an

inequality in terms of x and 1904 that is true only for values of x that represent years before the start of the Russo-Japanese War.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
6 0
The years when the Russo-Japanese war had not yet happened is the year of 1903 and before

Let x represents years, the inequality system is x < 1904
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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
PLEASE HELP PLEASE!!!
defon

Answer:

We conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

Therefore, the solution to f(x) = g(x) is:

  • x = -1
  • x - 0

Step-by-step explanation:

Given the table

x                f(x) = 2ˣ - 1                  g(x) = 1/2x

-2                  -3/4                               -1

-1                    -1/2                               -1/2

0                     0                                   0

1                       1                                   1/2

2                     3                                    1

If we carefully observe, we can determine that

at x = 0, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

In other words,

at x = 0

  • f(0) = 0
  • g(0) = 0

Thus,

at x = 0

f(x) = g(x)

Also at x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

In other words,

at x = -1

  • f(-1) = -1/2
  • g(-1) = -1/2

Thus,

at x = -1

f(x) = g(x)

Summary:

Thus, we conclude that at x = 0 and x = -1, the value of f(x) = 2ˣ - 1 and g(x) = 1/2x is the same.

Therefore, the solution to f(x) = g(x) is:

  • x = -1
  • x - 0
6 0
3 years ago
A}20<br>b}28<br>C}23<br>D}26<br>i need some help asap
DaniilM [7]
The answer would be 26 due to the fact that it’s just nearly above the 25 mark
3 0
3 years ago
MZRSK = x + 53, m KST = x + 109,<br> and mZRST = 156º<br><br><br> Find x.
Dahasolnce [82]

Answer:

-3 = x

Step-by-step explanation:

Since we are not given a midpoint, we use the Angle Addition Postulate:

156 = [x + 109] + [x + 53]

156 = 162 + 2x

-162 - 162

_______________

−6 = 2x

___ ___

2 2

−3 = x

[−3 + 53] + [−3 + 109] = 156

50 106

156 = 156 ☑

Therefore, -3 = xis a genuine statement.

I am joyous to assist you anytime.

4 0
3 years ago
A box has 59 cubic inches we need to find what is the length and width and also height explain how you got the answer and also s
kozerog [31]

Answer:

59÷4

you will find the answer

3 0
3 years ago
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