Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
d
Step-by-step explanation:
Answer:
Step-by-step explanation:
a-number of advance tickets
s-number of same day tickets
a*40+s*25=2400
a +s =75
I solve with the substitution method
s=75-a
40a+25*(75-a)=2400
40a+1875-25a=2400
15a=2400-1875
15a=525
a=525/15
a=35
so s=75-35
s=40
Answer: median and mean are the same
Step-by-step explanation:
The error committed by Michela is by saying
The median and mean are the same.
Because in statistics, we can't use mode to predict the median and the mean.