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sladkih [1.3K]
3 years ago
14

Consider the following pieces of identification a person might have in order to apply for a credit card:

Mathematics
1 answer:
love history [14]3 years ago
3 0

Answer:

B v D v M ;

(B ٨ M) V (B ٨ D) V (M ٨ D) ;

B V (D ٨ M)

Step-by-step explanation:

Given :

B : Applicant present a birth certificate

D: Applicant presents a drivers license

M applicant presents a marriage license

1.)

This means that any one of the three must be presented :

Birth certificate OR Driver's license OR Marriage certificate

B v D v M

2.)

This means any two combination of the three certificates :

(birth certificate and marriage certificate) OR (birth certificate and driver's license) OR (marriage certificate and driver's license)

(B ٨ M) V (B ٨ D) V (M ٨ D)

3.)

That is birth certificate alone will suffice or a driver's incense and a marriage certificate

B V (D ٨ M)

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Axis of symmetry of f(x)=(x+3)^2-8
Anna007 [38]

<u>ANSWER</u>

x =  - 3

<u>EXPLANATION</u>

When a quadratic equation is in the vertex form,

f(x) = a {(x - h)}^{2}  + k

the equation of axis of symmetry is simply

x = h

The given quadratic equation is

f(x) =  {(x + 3)}^{2}  - 8

We can rewrite this as

f(x) =  {(x  -  -  3)}^{2}  - 8

We now compare to

f(x) = a {(x - h)}^{2}  + k

We have

h =  - 3 \:  \:  \: and \:  \: k =  - 8

Therefore equation of axis of symmetry is:

x =  - 3

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3 years ago
Find the measurement of the two angles <br>Please !​
HACTEHA [7]

Answer:

1 -9 09u and than add

Step-by-step explanation:

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3 years ago
The manager of a dress shop recorded the number of dresses sold during the week the data is as follows
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5 0
4 years ago
The same survey database cited in exercise 4.3.1 (A-5) shows that 32 percent of U.S. adults indicated that they have been tested
yawa3891 [41]

Answer:

a. P(X = 3) = 0.145736

b. P(5≤X≤9) = 0.5462

c. P(5<X<10) = 0.3332

d. P(X≥6) = 0.3393

e. P(X<5) = 0.4477

f. Mean = 4.8, Variance = 3.264

Step-by-step explanation:

Given - The same survey database cited in exercise 4.3.1 (A-5) shows

             that 32 percent of U.S. adults indicated that they have been

             tested for HIV at some point in their life. Consider a simple

             random sample of 15 adults selected at a time. Let X be the

             number of adults who have been tested for HIV in the sample.

To find - For the following, find the numerical answer and describe

              the answer in words:

              a. Three

              b. Between five and nine, inclusive

              c. More than five, but less than 10

              d. Six or more

              e. Less than five

              f. Find the mean and the variance of the number of people

                 tested for HIV in samples of size 15.

Proof -

Given that , n = 15, p = 32% = 0.32

Now,

a.

P(X = 3) = binomial distribution (3, 15, 0.32, 0)

             = \left(\begin{array}{ccc}15\\3\end{array}\right)(0.32)^{3}(1-0.32)^{15 - 3}

             = 455(0.032768)(0.009774)

             = 0.145736

⇒P(X = 3) = 0.145736

b.

P(5≤X≤9) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

               = \left(\begin{array}{ccc}15\\5\end{array}\right)(0.32)^{5}(1-0.32)^{15 - 5}+ \left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6} + \left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7} + \left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}+ \left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}

               = 0.213 + 0.1671 + 0.1011 + 0.0476 + 0.0174

               = 0.5462

⇒P(5≤X≤9) = 0.5462

c.

P(5<X<10) = + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

                 =  \left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6} + \left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7} + \left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}+ \left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}

               =  0.1671 + 0.1011 + 0.0476 + 0.0174

               = 0.3332

⇒P(5<X<10) = 0.3332

d.

P(X≥6) = 1 - P(X < 6)

           = 1 - P(X ≤ 5)

           = 1 - binomial(5, 15, 0.32, 1)

           = 1 - 0.6607

           = 0.3393

⇒P(X≥6) = 0.3393

e.

P(X<5) = P(X≤4)

           = binomial (4, 15, 0.32, 1)

           = 0.4477

⇒P(X<5) = 0.4477

f.

Mean = np

         = 15(0.32)

         = 4.8

⇒Mean = 4.8

Variance = np(1-p)

              = 15(0.32)(1 - 0.32)

              = 4.8(0.68)

              = 3.264

⇒Variance = 3.264

3 0
3 years ago
Layla just started reading the book that she’s really into she has been reading four the last two hours and has read 110 pages s
Doss [256]
She can read 55 pages per hour
So, divide that by 2 to get 27.5
She can read 27.5 pages in the next 30 Min.
(She would be on page 137.5 :p)
Hope this helps!!
8 0
3 years ago
Read 2 more answers
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