Look below giving brainliest

A) Show that the equation 20-x^3-7x^2=0 can be rearranged to give x=20/x^2 - 7

AVprozaik [17]

Answer:

Step-by-step explanation:

$20-x^3-7x^2=0$

a)

Add $x^3$ to both sides of the equation: $20-7x^2=x^3$
Divide both sides by $x^2$ : $\frac{20}{x^2} -\frac{7x^2}{x^2} =\frac{x^3}{x^2}$ ⇒ $\frac{20}{x^2} -7 =x$

b)

$x_1=\frac{20}{(x_0)^2} -7$

⇒ $x_1=\frac{20}{(-9)^2} -7$

⇒ $x_1=-\frac{547}{81}$

$x_2=\frac{20}{(x_1)^2} -7$

⇒ $x_2=\frac{20}{(-\frac{547}{81})^2} -7$

⇒ $x_2=-6.561443673...$

$x_3=\frac{20}{(x_2)^2} -7$

⇒ $x_3=\frac{20}{(-6.561443673...)^2} -7$

⇒ $x_3=-6.535451368...$

c) approximation to the location of one of the roots of the equation. Each iteration gives a slightly more accurate value of a root $x$ .

4 0

3 years ago

BRAINLIEST TO EVERY ONE <br> WHO ANSWER THIS QUESTION<br> WITH A PROPER EXPLANATION

insens350 [35]

Answer:

4 tiles

Step-by-step explanation:

If the width is 84 cm, let's take a 84cm lengthed tile.

in the remaining part we get 112-84=28 cm

let's check whether 84÷ 28 is a whole number. if it's a whole number we can keep the n number of 28 cm length tile

84÷28=3

luckily we dont need to think a lot. just put 3, 28 cm tile in the balance part .

she only needs 4 tiles to fill the table

6 0

3 years ago

Ciro purchased a concert ticket for $56 . The cost of the ticket was 4/5 the cost of his dinner. The cost of his hotel was 2 1/2

NeTakaya

$266

<h3>Further explanation</h3>

<u>Given:</u>

Ciro purchased a concert ticket for $56.

The cost of the ticket was ⁴/₅ the cost of his dinner.

The cost of his hotel was 2¹/₂ times much as his ticket.

<u>Question:</u>

How much did Ciro spend altogether for the concert ticket, hotel, and dinner?

<u>The Process:</u>

Note from all the data above we can start from the cost of his dinner by forming a pattern of 5 units.

$Dinner: \boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}$

Since the cost of the ticket is ⁴/₅ the cost of the dinner, then we arrange the cost of the ticket by forming a pattern of 4 units containing $ 14 each. Recall that $\boxed{\$ 56 \div 4 = \$ 14}$

$Ticket: \boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14} = \$ 56$

Let us calculate the cost of his dinner:

$\boxed{ \ 1 \ unit = \$ 14 \rightarrow 5 \ units = \$ \ ? \ }$

$Dinner: \boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14}\boxed{\$ 14} = \$ 70}$

$\boxed{ \ \ or \ 5 \ unit \times \$ 14 = \$ 70 \ }$

Hence, the cost of his dinner is $\boxed{\boxed{ \ \$ 70 \ }}$

Since the cost of his hotel is 2¹/₂ times much as his ticket, then we arrange the cost of his hotel by forming a pattern of two and one-half units of the cost of ticket.

Let us calculate the cost of his hotel:

$\boxed{ \ 1 \ ticket = \$ 56 \rightarrow 2\frac{1}{2} \ units = \$ \ ? \ }$

$Hotel: \boxed{\$ 56}\boxed{\$ 56}\boxed{\$ 28} = \$ 140}$

$\boxed{ \ \ or \ \frac{5}{2} \ unit \times \$ 56 = \$ 140 \ }$

Recall that $\boxed{\ 2\frac{1}{2} = \frac{5}{2}}$

Hence, the cost of his hotel is $\boxed{\boxed{ \ \$ 140 \ }}$

In the final step, we calculate how much Ciro spend altogether for the concert ticket, hotel, and dinner.

$\boxed{ \ The \ concert \ ticket = \$ 56 \ }$

$\boxed{ \ The \ hotel = \$ 140 \ }$

$\boxed{ \ The \ dinner = \$ 70 \ }$

$\boxed{ \ \$ 56 + \$ 140 + \$ 70 = \$ 266 \ }$

Thus, Ciro spent $266 altogether for the concert ticket, hotel, and dinner.

<h3>Learn more</h3>

What is the width of the actual snowflake? brainly.com/question/1070912
How much does his cat weigh (Jesse's)? brainly.com/question/388037
How much more paint will Mathilde need to buy? brainly.com/question/36885

Keywords: Ciro purchased a concert ticket for $56, pattern, 4/5 the cost of his dinner, the cost of his hotel was 2 1/2 times much as his ticket, Ciro spend altogether

4 0

4 years ago

Read 2 more answers

What is the answer to this question???

Radda [10]

the answer to your question is -5×

5 0

4 years ago

A company makes Citi bikes. 95% (i.e., 0.95) pass final inspection. Suppose that 5 bikes are randomly selected.

Phoenix [80]

Answer:

Hi myself Shrushtee.

Step-by-step explanation:

Given,

p=0.95

n=5

1-p = q =1-0.95=0.05

a)Probability that exactly 4 of these 5 sports bikes pass final inspection =0.2036

b)Probability that less than 3 of these 5 sports bikes pass final inspection =0.0012

Please mark me as brainleist

8 0

3 years ago