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vredina [299]
3 years ago
9

Use a number line to solve equation -3+2+4-5= pleaseee helppppp

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

-2

Step-by-step explanation:

-3+2=-1

-1+4=3

3-5=-2

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The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by d=1.9[(5.5×10−4)L]1/2, where is the
amid [387]

The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm

<h3><u>Solution:</u></h3>

Given that,

<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>

d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}

where l is the length (in millimeters) of the camera box

<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>

l = 10 cm

We know that,

10 cm = 100 mm

<em><u>Therefore, plug in l = 100 in given formula</u></em>

d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446

Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm

6 0
3 years ago
Which property of addition does 8 + 0 = 0
cluponka [151]
This property of addition is the Identity Property. The identity property states that any number added to 0 will equal to the original number. 




Hope this helped☺☺


6 0
3 years ago
Do you guys know how to remember certain measurements?
Sholpan [36]
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6 0
3 years ago
If this trapezoid is moved through the
jeka94

Answer:

Step-by-step explanation:

A(-6,2) =>A'(-5, -1)

B(-5,4) =>B'( -4,1)

C(-2,4)=> C'(-1,1)

D( 1,2) => D'(2,-1)

we move all these points to (x+1, y-3)

7 0
2 years ago
Which is the graph of f (x) = 4 (1/2) Superscript x?
miss Akunina [59]

Answer:

Option (2) is correct graph.

Step-by-step explanation:

Given:

The function to graph is given as:

f(x)=4(\frac{1}{2})^x

Now, the above function is an exponential function of the form f(x)=ka^x

Where, 'k' and 'a' are constants.

The range of an exponential function is always greater than 0.

The domain is all real numbers.

Now, for graphing it, we need to find some points on it and its end behaviour.

Now, for x = 0, the function value is given as:

f(0)=4(\frac{1}{2})^0=4

So, (0, 4) is a point on the graph.

Now, for x = 1, the function value is given as:

f(1)=4(\frac{1}{2})^1=4\times\frac{1}{2}=2

So, (1, 2) is another point on the graph.

Now, for x = 2, the function value is given as:

f(2)=4(\frac{1}{2})^2=4\times\frac{1}{4}=1

So, (2, 1) is another point on the graph.

Now, as 'x' tends to ∞, the function value tends to:

f(x\to\infty)=4\cdot\frac{1}{2}^{\infty}=\frac{4}{\infty}=0

So, as

x\to\infty,f(x)\to0\\\\x\to-\infty,f(x)\to\infty

Now, from among all the options, only option (2) fulfills all the conditions given above.

So, option (2) is correct graph.

5 0
3 years ago
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