Find the equiaent expression of 3+2(2p+4t) A.12p+24t. B.4p+12t+6. C.4p+8t+3. D.10p+6t+3

1 answer:

3 0

Answer: C

Solving Steps: 3+2(2p+4t)

1) Multiply each term in the parentheses by 2
→2•2p+2•4t

2) Calculate the product
→ 3+(2•2)p+2•4t
→=3+4p+2•4t

→3+4p+(2•4)t
→=3+4p+8t
↑
This would be the final answer to the expression. 4p+8t+3 is the same answer but in different order.

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Step-by-step explanation:

Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.

<h3>Square</h3>

The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.

For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.

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<h3>Triangle</h3>

The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.

The area of the triangle is 24 square units.

<em>Additional comment</em>

We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.