1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aivan3 [116]
2 years ago
15

Give a regular expression for binary numbers. They can be integers or binary fractions. A leading - sign is always allowed. Lead

ing 0's are not allowed except when the integer part is 0. When the binary points is present, then neither the integer part nor the fractional part are allowed to be empty. If the integer part has more than 3 bits, then grouping with commas is required. Examples: Allowed: -0 1,111,010 -1,111.00 Not allowed: .11 1000 The 4-letter alphabet consists of 0, 1, dot, and comma.
Computers and Technology
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0

Solution :

We have to provide an expression for the binary numbers. There can be binary fractions or integers. Whenever there is leading 0, it is not allowed unless the integer part is a 0.

Thus the expression is :

$(-+ \in )$ $[(1+10+11+100+101+110+111)(,000+,001+,010+,011+,111+,100+,101+,110)^*$ $(\in +.(0+1)^*(0+1))+(0.(0+1)^*(0+1))]$

You might be interested in
Can someone please do this java lab for me (100 point version)? Heres the link: https://www.dropbox.com/sh/a639urhsggss051/AADdn
nlexa [21]

Answer:

não entendi DESCULPA kkkk

8 0
3 years ago
Which sql server 2012 edition is targeted at hosted, internet-facing deployment?
Mice21 [21]
<span>The Web version will work for this type of need. This version runs at a slightly lesser capability than the full version, but will still perform many of the advanced functions of SQL Server. The processor and RAM utilizations are a bit less than the maximum provided in other versions.</span>
7 0
3 years ago
You can view information for the individual people who will perform the tasks on theproject in the
marin [14]

Answer:

Resource Sheet view

8 0
2 years ago
Create a trigger that prevents anychange(insert, update, or delete)to the grade attribute of the takesrelation that would change
Dmitriy789 [7]
Omg co ol like chicken is funny sometimes
6 0
3 years ago
To iterate through (access all the entries of) a two-dimensional arrays you
ahrayia [7]

Answer: You would need two loops to iterate through both dimensions

Explanation:

matrix = [[1,2,3,4,5],

              [6,7,8,9,10],

              [11,12,13,14,15]]

for rows in matrix:

    for numbers in rows:

         print(numbers)

The first loop cycles through all the immediate subjects in it, which are the three lists. The second loop calls the for loop variable and iterates through each individual subject because they are lists. So the first loop iterates through the 1st dimension (the lists) and the seconds loop iterates through the 2nd dimension (the numbers in the lists).

6 0
3 years ago
Other questions:
  • If you’d like to have multiple italicized words in your document, how would you change the font of each of these words?
    7·2 answers
  • The class at the top of exception class hierarchy is ..........................
    12·1 answer
  • Why might a peer-to-peer network not be the best choice for a large corporate office setting?
    14·1 answer
  • What has information technology made piracy possible?
    14·1 answer
  • What is the statement describing? Agile team continuously adapt to new circumstances and enhance the methods of value delivery
    6·1 answer
  • What is the benefit of using a creative commons license?
    12·1 answer
  • Members of the sales team use laptops to connect to the company network. While traveling, they connect their laptops to the inte
    15·1 answer
  • How do you make a ringtone on earsketch
    9·1 answer
  • Why is it important to have a price assiociated in every product​
    10·2 answers
  • 1.<br> _g<br> clue: fret; become worried<br> 2.<br> Fret become worried
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!