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ahrayia [7]
3 years ago
11

To iterate through (access all the entries of) a two-dimensional arrays you

Computers and Technology
1 answer:
ahrayia [7]3 years ago
6 0

Answer: You would need two loops to iterate through both dimensions

Explanation:

matrix = [[1,2,3,4,5],

              [6,7,8,9,10],

              [11,12,13,14,15]]

for rows in matrix:

    for numbers in rows:

         print(numbers)

The first loop cycles through all the immediate subjects in it, which are the three lists. The second loop calls the for loop variable and iterates through each individual subject because they are lists. So the first loop iterates through the 1st dimension (the lists) and the seconds loop iterates through the 2nd dimension (the numbers in the lists).

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Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less
Ad libitum [116K]

Answer:

#include<iostream>//library inclusion

using namespace std;

int main()

{

int userInput;

do//start of do while loop

{

 cout << "Enter a number less than a 100" << endl;

 cin >> userInput;

 if (userInput < 100) //condition

 {

  cout << "YOu entered less than a hundred: " << userInput << endl;

 }

 else

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 }

} while (userInput > 100);//condition for do while

return 0;//termination of int main

}

Explanation:

The program has been commented for you. The do-while loop enters the first loop regardless of the condition. Then after the first iteration, it checks for the condition. If the condition is being met, it will iterate through, again. Otherwise it will break out of the loop and land on the "return 0;" line. Which also happens to be the termination of the program in this case. The if-else condition is used for the user to see when prompted.

6 0
3 years ago
True or false? Main Content (MC) may include links on the page.
nevsk [136]
True. 
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Sedbober [7]

Answer:

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Explanation:

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