Answer:
- sign = negative, degree = 5
Step-by-step explanation:
<u>The graph has negative leading coefficient as </u>
It is of the odd degree, and the degree is most probably 5
I think we have to use Pythagorean Therom here
a² + b² = c²
First we need to know the height of the Triangle (which is YT)
Let "b" be the height YT:
22² + b² = 77²
484 + b² = 5929
b² = 5929 - 484 = 5445
√b² = √(5445)
b = √5445 = 73.79ft
Now that we have the height lets find the missing base(YK):
We are going to use the same formula, but this time to find the base and with a different triangle.
a² + 73.79² = 87.5²
a² + 5444.96 = 7656.25
a² = 7656.25 - 5444.96
a² = 2211.29
√a² = √(2211.29)
a = √2211.29 = 47.02
Now we can add the bases together to find x.
Bases "VY" and "YK"
x = 22+47
x = 69
The second one is the correct answer!
Answer:
i cannot understand
Step-by-step explanation:
Answer:
1/35
Step-by-Step Explanation:
1. We can think about this problem as the probability of 3 events happening.
The first event is the teacher choosing one student who does not play soccer. The second event is the teacher choosing another student who does not play soccer, given that the teacher already chose someone who does not play soccer , and so on.
2. The probability that the teacher will choose someone who does not play soccer is the number of students who do not play soccer divided by the total number of students: 3/7.
3. Once the teacher's chosen one student, there are only 6 left.
4. There's also one fewer student who does not play soccer, since the teacher isn't going to pick the same student twice.
5. So, the probability that the teacher picks a second student who also does not play soccer is 2/6.
6. The probability of the teacher picking two students who do not play soccer must then be 3/7*2/6.
7. We can continue using the same logic for the rest of the students the teacher picks.
8. So, the probability of the teacher picking 333 students such that none of them play soccer is:
3/7*2/6*1/5=6/210=1/35