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trapecia [35]
4 years ago
12

1.what integer and -8 have the product -96?

Mathematics
1 answer:
Olegator [25]4 years ago
5 0
12 is your answer. you're welcome
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How to solve (with steps)<br> 3 ( x + 2 ) = 9 ( 6 - x )
Veseljchak [2.6K]

Answer: x = 4

Step-by-step explanation:

Distribute the 3 and the 9

3(x+2)=9(6-x)\\3x+6=54-9x

Add 9x to both sides

12x+6=54

Subtract 6 on both sides and simplify

12x = 48\\x=4

3 0
3 years ago
Read 2 more answers
The problem is in the picture
nikklg [1K]
We have to reverse what was already done to the number 19, so we’ll multiply it by 3 to get 57. We then subtract 8 from it to get 49. Therefore, the original number is 49.
7 0
4 years ago
Can anyone help me find the area of the circle
agasfer [191]

Answer:

C = 2·π·r. Se multiplicarmos o raio da circunferência por 2, encontraremos a medida do diâmetro (segmento de reta que intercepta dois pontos da circunferência passando pelo centro). ...

C = π·d. Como calcular a área de um círculo? ...

A = π·r²

Step-by-step explanation:

4 0
3 years ago
What is the mean of this set: {2, 6, 7, 9, 9, 9)?<br> 6<br> 7<br> Ο Ο Ο Ο<br> 8<br> 9
vovikov84 [41]

Answer:

6.8 nearly 7

Step-by-step explanation:

beacuse mean is sum of all terms in a data/number of terms in the data

3 0
3 years ago
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Finda + b, 8a + 9b, |a|, and |a − b|.(Simplify your answer completely.)a =leftangle0.gif−3, 4rightangle0.gifb =leftangle0.gif9,
alekssr [168]

Answer:

Step-by-step explanation:

Given the following vectors a = (-3,4) and b = (9, -1)

|a| and |b| are the modulus of a and b respectively.

|a| = √(-3)²+4²

|a| = √9+16

|a| = √25

|a| = 5

Similarly;

|b| = √(9)²+1²

|b| = √81+1

|b| = √82

We are to find the following;

a) a + b

a+b =  (-3,4)  +  (9, -1)

a+b = (-3+9, 4+(-1))

a+b = (6, 4-1)

a+b = (6,3)

b) 8a + 9b

8a + 9b = 8(-3,4)  + 9(9, -1)

8a + 9b = (-24,32)  + (81, -9)

8a + 9b = (-24+81, 32+(-9))

8a + 9b = (57, 32-9)

8a + 9b = (57, 23)

c) |a| = √(-3)²+4²

|a| = √9+16

|a| = √25

|a| = 5

d)  |a − b|

To get  |a − b|, we need to get a-b first

Solve for a -b

a-b =  (-3,4)  -  (9, -1)

a-b = (-3-9, 4-(-1))

a-b = (-12, 4+1)

a-b = (-12,5)

Find modulus of a-b i.e   |a − b|,

|a − b| = √(-12)²+5²

|a − b| = √144+25

|a − b| =√169

|a − b| = 13

6 0
3 years ago
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