Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
The is no number.I hope this helps
angle 1 = 180-110 = 70 degrees (linnear pair)
angle 2= 180-115 = 65 degrees (linnear pair)
angle 3 = angle 2 = 65 degrees (corresponding angles)
angle 4= 180 - angle 3 = 180-65 = 115 degrees (linnear pair)
(your teacher might not like this, depends on the cituation, but use 180 degrees in triangle to get 7)
angle 7 = 180 -angle1 -angle 2= 180-70-65= 45 degrees
angle 6 = angle 7 = 45 degrees ( vertical angles)
angle 8= 180- angle 7= 180-45 = 135 ( linnear pair)
angle 9 =angle 6 = 45 degrees (corresponding angles)
angle 5=angle 9=45 degrees (vertical angles)
Step-by-step explanation:
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