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vekshin1
3 years ago
6

Write an equivalent expression to (-0.25x - 3) - (2.5x + 1.7) using the fewest possible terms.

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

Answer: -2.75*x - 4.7

Step-by-step explanation:

In the equation we have only one variable, this means that the minimum possible number of terms will be two, one term with x, and one term without x.

We can start with the equation:

(-0.25x - 3) - (2.5x + 1.7)

Now, let's rewrite this as:

-0.25x - 3 - 2.5x - 1.7

(-0.25*x - 2.5*x) + (-3 - 1.7)

Solving the parentheses we get:

-2.75*x - 4.7

That is the equivalent expression that has the fewest possible terms

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Russ is solving an equation where both sides are linear expressions. he sets the expressions equal to y and graphs the system fi
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The correct  option (D).

There are infinitely many intersection points.

<h3>What is liner equation?</h3>

a two-variable equation that, when plotted on a graph, results in a straight line.

<h3>What does intersection point mean?</h3>

The term "point of intersection" refers to the intersection of two lines.

<h3>According to the given information:</h3>

Russ is attempting to solve an equation whose two sides are both linear expressions.

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Since both lines are the same, there are an endless number of junction places.

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I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

A. There are no intersection points.

B. There is exactly one intersection point.

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What are the fourth roots of 6+6√(3i) ?
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Answer:

Step-by-step explanation:

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∅ is teh argument = arctan y/x

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When n = 1;

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when n = 2;

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z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

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3 years ago
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