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3 years ago

I NEED HELP WITH 11-16 PLSSSSSS HELP ME ILL GIVE YOU BRAINLIESTTTTTTTT

Mathematics

2 answers:

Svetllana [295]3 years ago

4 0

Answer:-5

Step-by-step explanation:

Masteriza [31]3 years ago

3 0

11) 4

12) $6.66 a min

13) 25¢

14) Alexander

15) C. 22.50

16) C

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How do you round numbers

Mariulka [41]

Step 1: Circle the place value of the digit to be rounded. This is the rounding digit. Step 2: Look to the neighboring digit on the right. Step 3: a) If the neighboring digit is less than five (0 - 4), keep the rounding digit the same.

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3 years ago

candace tells you that she bought new boots using a 20% coupon and saved $28.What was the original price of the boots?use a tape

kkurt [141]

Answer:

Step-by-step explanation:

40 x 76 is the equation by 4x4 of 86 and the 36

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3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection.

This means that,

Probability that at least one of them needs replacement at the first inspection =

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Richard’s checking account balance was $57.34 at the beginning of the week. During the week, he recorded the transactions below.

Tomtit [17]

Answer:

US$ 132.45

Step-by-step explanation:

See attachment for the missing table.

Given:

Richard’s checking account balance at the beginning of the week = $57.34

Richard’s account balance at the end of the week from the given table:

Deposits of the week = US$ 163.75

Expenses of the week = Groceries + Credit card bill + Gas

Expenses of the week = 25.37 + 50 + 13.27

Expenses of the week = US$ 88.64

Richard’s account balance at the end of the week = Richard’s checking account balance at the beginning of the week + Deposits of the week - Expenses of the week

Replacing with the real values:

Richard’s account balance at the end of the week = 57.34 + 163.75 - 88.64

=US$ 132.4

7 0

3 years ago

Read 2 more answers

You pay $30 each month for satellite TV, plus $2.50 for every movie you purchase. Write and solve an equation to find the number

raketka [301]

The initial payment per month being 30 and each movie being 2.50 means that if the total payment is 45 then you pay for 6 movies per month, 30x+6(2.5x)

7 0

3 years ago

Read 2 more answers