Answer:
76.1g
Explanation:
The balanced equation for this reaction is as follows:
3NaOH + AlCl3 --> Al(OH)3 + 3NaCI
From the above equation, it can be observed that 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Using the formula below, we convert the mass of NaCl to moles;
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 100/58.5
mole = 1.71mol of NaCl
Since 1 mole of AlCl3 is needed to produce 3 moles of NaCl.
Then 1.71 moles of NaCl will be produced by 1.71/3 = 0.57mol of AlCl3
Molar mass of AlCl3 = 27 + 35.5(3)
= 27 + 106.5
= 133.5g/mol
Mole = mass/molar mass
Mass = molar mass × mole
Mass = 133.5 × 0.57
Mass = 76.1g
