<u>Answer:</u> The molarity of solution will be 0.049 M
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
We are given:
Given mass of sodium chloride = 10 g
Molar mass of sodium chloride = 58.44 g/mol
Volume of solution = 3.50 L
Putting values in above equation:
Hence, the molarity of solution will be 0.049 M
Whether water is frozen, in a gaseous state, or is a liquid, it is still H2O. So the chemical composition does stay the same.
Answer:
0.333 mol NH₃
Explanation:
N₂ + 3 H₂ ⇆ 2 NH₃
This is the reaction that produces NH₃. Use the mole ratios to solve. For every 3 moles of H₂ that are consumed, 2 moles of NH₃ are produced.
(0.500 mol H₂) × (2 mol NH₃/3 mol H₂) = 0.333 mol NH₃
You will produce 0.333 moles of NH₃.
Answer:
T2 = 29°C
Explanation:
Given data:
Heat added = 420 j
Mass of water = 25 g
Initial temperature = 25°C
Final temperature = ?
Solution;
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water = 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values.
420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)
420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)
420 j = 104.5 j/°C × (T2 - 25°C)
420 j /104.5 j/°C = T2 - 25°C
4°C + 25°C = T2
T2 = 29°C
