Answer:
85.8 g
Explanation:
The molar mass of BaCl₂ is 208.233 g/mol, so 210.1 g is about ...
210.1/208.233 ≈ 1.009 mol
The molar mass of K is about 39.089 g/mol, so 45 g is about ...
45/39.089 ≈ 1.1509 mol
The balanced equation seems to be ...
BaCl₂ + 2K ↔ 2KCl + Ba
This reaction requires 2 moles of potassium for each mole of barium chloride, so the available potassium limits the reaction. The result is as many moles of potassium chloride as there are moles of potassium.
The 1.1509 moles of KCl, at 74.551 g/mol will have a mass of about 85.8 g.
The reaction produces 85.8 g of KCl.
Answer:
![r=k[UO_2^+]^2[H^+]](https://tex.z-dn.net/?f=r%3Dk%5BUO_2%5E%2B%5D%5E2%5BH%5E%2B%5D)
Explanation:
The given reaction is :-
According to the law of mass action:-
The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
m = 2 = is order with respect to 
n = order with respect to H+
overall order = m+n = 3
n = 3 - m = 3 - 2 = 1
Rate law is:-
Answer:
26.8 °C
Explanation:
Step 1: Given and required data
- Energy transferred to the water (Q): 2100 J
- Initial temperature of the water (T₂): 23.6 °C
- Final temperature of the water (T₁): ?
- Specific heat of water (c): 4.184 J/g.°C
Step 2: Calculate the final temperature of the water
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C
D.It can not be separated by a physical change.
