Answer:
0.33 mol/kg NH₃
Explanation:
Data:
b(NH₃) = 0.33 mol/kg
b(Na₂SO₄) = 0.10 mol/ kg
Calculations:
The formula for the boiling point elevation ΔTb is
i is the van’t Hoff factor — the number of moles of particles you get from a solute.
(a) For NH₃,
The ammonia is a weak electrolyte, so it exists almost entirely as molecules in solution.
1 mol NH₃ ⟶ 1 mol particles
i ≈ 1, and ib = 1 × 0.33 = 0.33 mol particles per kilogram of water
(b) For Na₂SO₄,
Na₂SO₄(aq) ⟶ 2Na⁺(aq) + 2SO₄²⁻(aq)
1 mol Na₂SO₄ ⟶ 3 mol particles
i = 1 and ib = 3 × 0.10 = 0.30 mol particles per kilogram of water
The NH₃ has more moles of particles, so it has the higher boiling point.
Answer:
The answer to your question is letter B
Explanation:
A.) 2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 4
2 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
B.) 2 AgCl + Na2S ⟶ Ag2S + 2 NaCl
Reactants Elements Products
2 Ag 2
2 Cl 2
2 Na 2
1 S 1
This reaction is balanced
C.) AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl
Reactants Elements Products
1 Ag 4
1 Cl 2
2 Na 2
1 S 2
This reaction is unbalanced
D.) 2 AgCl + 2 Na2S ⟶ Ag2S + NaCl
Reactants Elements Products
2 Ag 4
2 Cl 1
4 Na 1
2 S 1
This reaction is unbalanced
Answer:
they all have one common function which is to pump blood and Arteries carry blood away from the heart; the main artery is the aorta. ... Capillaries carry blood away from the body and exchange nutrients, waste, and oxygen with tissues at the cellular level. Veins are blood vessels that bring blood back to the heart and drain blood from organs and limbs.
Explanation:
The answer should be B, it reacts in air to form a green layer.
Chemical properties means that how the substance that reacts with other substance to produce new substances. Usually it cannot be measured or observed just with the substance itself.
From all the options above, only B is a reaction. The green layer formed is a new substance produced by copper and air. It involves a chemical change.
Other options like boiling points or state of matter, these are physical properties. They do not require it to react to other substances and the can be measured and observed easily.
